Q.The aqueous solution having maximum boiling point is
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Boiling Point Elevation — From Intuition to Precision
Imagine you're cooking pasta. You add salt to the water, and the water takes longer to boil. That's not your imagination — it's a real physical effect. The salt has raised the boiling point of the water. Pure water boils at 100°C at sea level, but salt water needs a slightly higher temperature to boil. That's boiling point elevation in action.
Why does this happen?
To understand why, you need to think about what boiling actually is. Boiling occurs when the vapour pressure of the liquid equals the surrounding atmospheric pressure. Vapour pressure is the pressure exerted by molecules escaping from the liquid surface into the gas phase.
When you dissolve a non-volatile solute (like salt, which doesn't evaporate) in a solvent (like water), something interesting happens at the surface. Some of the surface molecules are now solute particles — they don't escape into the vapour. This means fewer solvent molecules can leave the liquid per second. The result? The vapour pressure of the solution is lower than that of the pure solvent at the same temperature.
Now, to make this reduced vapour pressure equal to the atmospheric pressure (so the liquid can boil), you need to raise the temperature. That extra heat gives the remaining solvent molecules enough energy to overcome the solute's interference and produce the required vapour pressure.
The solute itself doesn't boil away — it stays behind. That's why we call it a non-volatile solute. If the solute were volatile (like alcohol), the story changes.
The precise statement
Boiling point elevation is the increase in the boiling point of a solvent when a non-volatile solute is dissolved in it. The boiling point of the solution is always higher than that of the pure solvent.
The elevation ΔTb is given by:
ΔTb=Tb(solution)−Tb(pure solvent)
And it depends only on the number of solute particles, not on their chemical identity (for dilute solutions). This is a colligative property — a property that depends on the concentration of particles, not their nature.
ΔTb=Kb⋅m
Where:
- ΔTb = boiling point elevation (in °C or K)
- Kb = ebullioscopic constant of the solvent (a fixed value for each solvent)
- m = molality of the solution (moles of solute per kg of solvent)
What is Kb?
The ebullioscopic constant Kb is a property of the pure solvent. It tells you how much the boiling point rises per unit molal concentration. For water, Kb=0.512°C kg mol−1. So a 1 molal aqueous solution (1 mole of solute per kg of water) boils at 100.512°C.
For quick calculations: ΔTb∝m. Double the molality, double the elevation. But this works only for dilute solutions — at high concentrations, interactions between solute particles break the linearity.
What about electrolytes?
If the solute dissociates into ions (like NaCl → Na⁺ + Cl⁻), the number of particles increases. One mole of NaCl gives two moles of particles in solution. So the effective concentration is higher. We account for this using the van't Hoff factor i:
ΔTb=i⋅Kb⋅m
For NaCl, i≈2 (in dilute solutions). For sugar (which doesn't dissociate), i=1. …
Why this formula?
Boiling Point Elevation: Why the Formula Holds
Let's build this from first principles — understanding the why before the what.
What Happens at the Boiling Point?
At the boiling point, a liquid's vapor pressure equals the external atmospheric pressure. For a pure solvent, this happens at a fixed temperature (e.g., 100°C for water at 1 atm).
When you add a non-volatile solute (like salt or sugar), the solute particles occupy space at the liquid surface, reducing the number of solvent molecules that can escape into vapor. This lowers the vapor pressure of the solution compared to the pure solvent.
The Key Consequence
Since vapor pressure is now lower, the solution must be heated to a higher temperature to make its vapor pressure reach atmospheric pressure again. That's the boiling point elevation.
The Formula and Its Derivation
The boiling point elevation ΔTb is given by:
ΔTb=Kb⋅m
where:
- ΔTb=Tb(solution)−Tb(pure solvent)
- Kb = ebullioscopic constant (depends only on the solvent)
- m = molality of the solution (moles of solute per kg of solvent)
Why Molality and Not Molarity?
Molality is temperature-independent — it doesn't change when the solution is heated. Molarity (moles per liter) changes because volume expands with temperature. Since we're measuring a temperature change, we need a concentration unit that stays fixed.
The Reasoning Behind Kb
The constant Kb comes from thermodynamics. For a dilute solution, the vapor pressure lowering follows Raoult's Law:
Psolution=xsolvent⋅Psolvent0
where xsolvent is the mole fraction of solvent and Psolvent0 is the pure solvent's vapor pressure.
Using the Clausius-Clapeyron equation (which relates vapor pressure to temperature) and Raoult's Law, one can derive:
Kb=1000⋅ΔHvapRTb2
where:
- R = gas constant (8.314 J/mol·K)
- Tb = boiling point of pure solvent (in Kelvin)
- ΔHvap = molar enthalpy of vaporization (J/mol)
- The factor 1000 converts grams to kg (since molality uses kg of solvent)
What This Tells Us
- Kb is a property of the solvent alone — it doesn't depend on the solute.
- Solvents with higher boiling points or lower heats of vaporization have larger Kb values (greater elevation per molal concentration).
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Elevation of boiling point is a colligative property, so the solution with the greatest number of dissolved particles (molarity times van't Hoff factor i) boils highest. …
Boiling point rises with total dissolved particle concentration (i x M); Na2SO4 gives 0.01 x 3 = 0.03 M, the largest, so option (d).
Elevation of boiling point (delta Tb = i x Kb x m) depends on the total number of dissolved particles, i.e. on the product of molarity and the van't Hoff factor i (number of particles per formula unit).
- (a) 0.015 M glucose: i = 1 -> 0.015
- (b) 0.01 M KNO3: i = 2 (K+ + NO3-) -> 0.020 …
- CBSE 2019Set ANNUAL1 markMCQQ.The aqueous solution having maximum boiling point is(a) 0.015 M glucose(b) 0.01 M KNO3(c) 0.015 M urea(d) 0.01 M Na2SO4
›Reveal solutionSolution
Boiling point rises with total dissolved particle concentration (i x M); Na2SO4 gives 0.01 x 3 = 0.03 M, the largest, so option (d).
Elevation of boiling point (delta Tb = i x Kb x m) depends on the total number of dissolved particles, i.e. on the product of molarity and the van't Hoff factor i (number of particles per formula unit).
- (a) 0.015 M glucose: i = 1 -> 0.015
- (b) 0.01 M KNO3: i = 2 (K+ + NO3-) -> 0.020 …
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