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Q.Find two positive numbers whose sum is 1515 and the sum of their squares is minimum.

Uttar Pradesh UpmspUP Board (UPMSP) Intermediate 2024Subjective· 5mImportance★★★★★
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Let the numbers be xx and 15−x15-x. Minimizing S=x2+(15−x)2S=x^2+(15-x)^2 gives x=7.5x=7.5, so both numbers are 7.57.5.

Concept. Express the quantity to minimize as a function of one variable using the constraint, then use dSdx=0\dfrac{dS}{dx}=0 and the second-derivative test.

Set up. Let the numbers be xx and 15−x15-x (both positive, so 0<x<150<x<15). Sum of squares:

S(x)=x2+(15−x)2.S(x)=x^2+(15-x)^2.

Differentiate.

dSdx=2x+2(15−x)(−1)=4x−30.\frac{dS}{dx}=2x+2(15-x)(-1)=4x-30.

Set dSdx=0⇒x=304=152=7.5.\dfrac{dS}{dx}=0\Rightarrow x=\dfrac{30}{4}=\dfrac{15}{2}=7.5.

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