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Question of 146

Q.Solve the following system of equations by Cramer's Rule: x+2y−3z=−4x + 2y - 3z = -4, 2x+3y+2z=22x + 3y + 2z = 2, 3x−3y−4z=113x - 3y - 4z = 11.

Uttar Pradesh UpmspUP Board (UPMSP) Intermediate 2018Subjective· 4mImportance★★★★★
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D = 67, Dx = 201, Dy = −134, Dz = 67, so x = 3, y = −2, z = 1.

System: x + 2y − 3z = −4, 2x + 3y + 2z = 2, 3x − 3y − 4z = 11.

Step 1: Coefficient determinant

D = | 1, 2, −3 ; 2, 3, 2 ; 3, −3, −4 |

= 1(3·(−4) − 2·(−3)) − 2(2·(−4) − 2·3) + (−3)(2·(−3) − 3·3)

= 1(−12 + 6) − 2(−8 − 6) − 3(−6 − 9)

= −6 + 28 + 45 = 67.

Step 2: Dx (replace column 1 by the constants −4, 2, 11):

Dx = | −4, 2, −3 ; 2, 3, 2 ; 11, −3, −4 |

= −4(−12 + 6) − 2(−8 − 22) − 3(−6 − 33)

= 24 + 60 + 117 = 201.

Step 3: Dy (replace column 2):

Dy = | 1, −4, −3 ; 2, 2, 2 ; 3, 11, −4 |

= 1(2·(−4) − 2·11) + 4(2·(−4) − 2·3) − 3(2·11 − 2·3)

= (−30) + 4(−14) − 3(16) = −30 − 56 − 48 = −134. …

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