Q.Solve the following system of equations by Cramer's Rule: , , .
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System: x + 2y − 3z = −4, 2x + 3y + 2z = 2, 3x − 3y − 4z = 11.
Step 1: Coefficient determinant
D = | 1, 2, −3 ; 2, 3, 2 ; 3, −3, −4 |
= 1(3·(−4) − 2·(−3)) − 2(2·(−4) − 2·3) + (−3)(2·(−3) − 3·3)
= 1(−12 + 6) − 2(−8 − 6) − 3(−6 − 9)
= −6 + 28 + 45 = 67.
Step 2: Dx (replace column 1 by the constants −4, 2, 11):
Dx = | −4, 2, −3 ; 2, 3, 2 ; 11, −3, −4 |
= −4(−12 + 6) − 2(−8 − 22) − 3(−6 − 33)
= 24 + 60 + 117 = 201.
Step 3: Dy (replace column 2):
Dy = | 1, −4, −3 ; 2, 2, 2 ; 3, 11, −4 |
= 1(2·(−4) − 2·11) + 4(2·(−4) − 2·3) − 3(2·11 − 2·3)
= (−30) + 4(−14) − 3(16) = −30 − 56 − 48 = −134. …
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