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Q.A ray of light incident on face AB of an equilateral glass prism, shows minimum deviation angle of 30°. Calculate the speed of light through the prism. Find the angle of incidence at the face AB so that the emergent ray grazes along the face AC. Given: Speed of light in vacuum = 3 × 10^8 ms^-1 and sin15° = (√3 − 1)/(2√2).

Uttar Pradesh UpmspUP Board (UPMSP) Intermediate 2019Subjective· 5mImportance★★★★★
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μ = √2 → v ≈ 2.12×10⁸ m/s; grazing at AC needs critical angle 45°, giving i ≈ 21.5°.

Step 1 — refractive index and speed of light in the prism:

For an equilateral prism, A = 60°, and at minimum deviation δ_min = 30°:

μ = sin((A + δ_min)/2) / sin(A/2) = sin((60 + 30)/2)/sin(30) = sin45°/sin30° = (1/√2)/(1/2) = √2.

Speed of light in the prism:

v = c/μ = (3 × 10⁸)/√2 ≈ 2.12 × 10⁸ m/s.

Step 2 — angle of incidence for the emergent ray to graze face AC:

'Grazing along AC' means the ray emerges at 90° to the normal at AC, so the angle of refraction at AC is 90°, which means the angle of incidence inside at AC equals the critical angle C:

sin C = 1/μ = 1/√2 ⇒ C = 45°.

For a prism, the two internal refraction angles satisfy r₁ + r₂ = A. Here r₂ = C = 45°, so

r₁ = A − r₂ = 60° − 45° = 15°.

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