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Question of 135

Q.(a) Give two reactions that show the acidic nature of phenol. [2]

(b) Give chemical reaction for the preparation of phenol from chlorobenzene. [1]
(OR)
Write IUPAC names of the following compounds - [1+1+1=3]
(a) CH3-CH(Cl)-CH(CH3)-CH(CH3)-CH2OH [pentane chain: C1=CH3, C2 bears Cl, C3 bears CH3, C4 bears CH3, C5=CH2OH; the only -OH is the terminal CH2OH]
(b) CH3-CH(CH3)-O-CH2-CH3 [isopropyl ethyl ether]
(c) [FIGURE: a benzene ring bearing an -OH group at one carbon and a -CH3 group on each of the two carbons ortho to it - 2,6-dimethylphenol]
Uttarakhand UbseUttarakhand Board Intermediate (Class 12) 2022Subjective· 3mImportance★★★★★
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(a) Phenol behaves as a weak acid: it reacts with NaOH (a base) and with active metals like Na (releasing H2) - genuine tests of the acidic -OH that ordinary alcohols do not give with NaOH. (b) Phenol is made industrially from chlorobenzene only under forcing conditions (NaOH, 623 K, 300 atm - the Dow process). OR: IUPAC naming of the three drawn structures.

(a) Two reactions showing the acidic nature of phenol (its -OH hydrogen is far more acidic than an alcohol's, because the phenoxide ion formed is resonance-stabilised by the aromatic ring):

  1. Reaction with aqueous sodium hydroxide (a true acid-base reaction - alcohols do NOT react with NaOH, but phenol does): C6H5OH + NaOH -> C6H5ONa (sodium phenoxide) + H2O.
  2. Reaction with reactive/active metals such as sodium, evolving hydrogen gas: 2C6H5OH + 2Na -> 2C6H5ONa + H2(g). The reaction with NaOH is the more diagnostic of the two, because only compounds with a sufficiently acidic -OH (phenols and carboxylic acids) react with a base like NaOH, whereas simple alcohols do not.

(b) Preparation of phenol from chlorobenzene requires drastic conditions because the C-Cl bond in chlorobenzene has partial double-bond character (chlorine's lone pair is donated into the ring by resonance) and resists nucleophilic substitution. Chlorobenzene is heated with aqueous NaOH at about 623 K under about 300 atm pressure (the Dow process) to give sodium phenoxide, which is then acidified to liberate phenol:

C6H5Cl + 2NaOH --623 K, 300 atm--> C6H5ONa + NaCl + H2O

C6H5ONa + HCl -> C6H5OH + NaCl.

OR (alternative - IUPAC naming):

(a) The drawn structure is CH3-CH(Cl)-CH(CH3)-CH(CH3)-CH2OH: a five-carbon chain whose only -OH is the terminal CH2OH, with a -Cl and two -CH3 branches along the chain. The -OH is the principal characteristic group, so it must get the lowest locant; numbering therefore starts from the CH2OH end. C1 = CH2OH, C2 = CH(CH3), C3 = CH(CH3), C4 = CH(Cl), C5 = CH3. This is an alcohol (pentan-1-ol), NOT a diol, carrying a 4-chloro substituent and two methyls at C2 and C3.

IUPAC name: 4-chloro-2,3-dimethylpentan-1-ol.

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