Q.(a) Give two reactions that show the acidic nature of phenol. [2]
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →(a) Phenol behaves as a weak acid: it reacts with NaOH (a base) and with active metals like Na (releasing H2) - genuine tests of the acidic -OH that ordinary alcohols do not give with NaOH. (b) Phenol is made industrially from chlorobenzene only under forcing conditions (NaOH, 623 K, 300 atm - the Dow process). OR: IUPAC naming of the three drawn structures.
(a) Two reactions showing the acidic nature of phenol (its -OH hydrogen is far more acidic than an alcohol's, because the phenoxide ion formed is resonance-stabilised by the aromatic ring):
- Reaction with aqueous sodium hydroxide (a true acid-base reaction - alcohols do NOT react with NaOH, but phenol does): C6H5OH + NaOH -> C6H5ONa (sodium phenoxide) + H2O.
- Reaction with reactive/active metals such as sodium, evolving hydrogen gas: 2C6H5OH + 2Na -> 2C6H5ONa + H2(g). The reaction with NaOH is the more diagnostic of the two, because only compounds with a sufficiently acidic -OH (phenols and carboxylic acids) react with a base like NaOH, whereas simple alcohols do not.
(b) Preparation of phenol from chlorobenzene requires drastic conditions because the C-Cl bond in chlorobenzene has partial double-bond character (chlorine's lone pair is donated into the ring by resonance) and resists nucleophilic substitution. Chlorobenzene is heated with aqueous NaOH at about 623 K under about 300 atm pressure (the Dow process) to give sodium phenoxide, which is then acidified to liberate phenol:
C6H5Cl + 2NaOH --623 K, 300 atm--> C6H5ONa + NaCl + H2O
C6H5ONa + HCl -> C6H5OH + NaCl.
OR (alternative - IUPAC naming):
(a) The drawn structure is CH3-CH(Cl)-CH(CH3)-CH(CH3)-CH2OH: a five-carbon chain whose only -OH is the terminal CH2OH, with a -Cl and two -CH3 branches along the chain. The -OH is the principal characteristic group, so it must get the lowest locant; numbering therefore starts from the CH2OH end. C1 = CH2OH, C2 = CH(CH3), C3 = CH(CH3), C4 = CH(Cl), C5 = CH3. This is an alcohol (pentan-1-ol), NOT a diol, carrying a 4-chloro substituent and two methyls at C2 and C3.
IUPAC name: 4-chloro-2,3-dimethylpentan-1-ol.
…
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.