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Q.Read the following passage carefully and answer the questions given below –
Carboxylic acids are reduced to corresponding primary alcohols by Lithium aluminium hydride (LiAlH₄) or with diborane (B₂H₆). Diborane does not easily reduce functional groups such as ester, nitro, halo etc. Carboxylic acids having an α-hydrogen, on treatment with chlorine or bromine in the presence of small amount of red phosphorus give α-halocarboxylic acids. Sodium salts of carboxylic acids upon heating with soda lime (NaOH and CaO in the ratio of 3:1) lose carbon dioxide and hydrocarbons are formed. Aromatic carboxylic acids undergo electrophilic substitution reactions in which the carboxyl group acts as a deactivating and meta-directing group. They however, do not undergo Friedel-Crafts reaction because the carboxyl group is deactivating and the catalyst aluminium chloride (Lewis acid) gets bonded to the carboxyl group.

(a) How will you convert ethanoic acid to 2-bromoethanoic acid? Give only chemical equation.
(b) Benzoic acid does not undergo Friedel-Crafts reaction. Give reason.
(c) Complete the following reaction: R—COOH —(i)B₂H₆ / (ii)H₃O⁻→
(d) What happens when sodium ethanoate is heated with sodalime? Give only chemical equation.
Uttarakhand UbseUttarakhand Board Intermediate (Class 12) 2026Subjective· 4mImportance★★★★★
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(a) α-Bromination of ethanoic acid is the Hell–Volhard–Zelinsky reaction (Br₂/red P). (b) Benzoic acid's –COOH is deactivating and coordinates AlCl3\text{AlCl}_3, so no Friedel–Crafts. (c) B2H6\text{B}_2\text{H}_6 reduces –COOH to a primary alcohol. (d) Sodium ethanoate + soda lime undergoes decarboxylation to methane.

(a) Ethanoic acid → 2-bromoethanoic acid (HVZ reaction). A carboxylic acid with an α\alpha-hydrogen reacts with Br2\text{Br}_2 in the presence of a little red phosphorus to give the α\alpha-bromo acid:

CH3COOH→red PBr2BrCH2COOH+HBr\text{CH}_3\text{COOH} \xrightarrow[\text{red P}]{\text{Br}_2} \text{BrCH}_2\text{COOH} + \text{HBr}

(2-bromoethanoic acid = bromoacetic acid).

(b) Why benzoic acid gives no Friedel–Crafts reaction. As the passage states, the carboxyl group is a deactivating, meta-directing group that pulls electron density out of the ring. Moreover, the catalyst AlCl3\text{AlCl}_3 (a Lewis acid) becomes bonded to the lone pairs of the carboxyl group, making the ring still more electron-deficient. With so little electron density, the ring cannot attack the electrophile, so Friedel–Crafts alkylation/acylation does not occur.

(c) Diborane reduction. Diborane reduces carboxylic acids to the corresponding primary alcohols (it does not touch ester/nitro/halo groups):

R–COOH→(ii) H3O+(i) B2H6R–CH2OH\text{R–COOH} \xrightarrow[\text{(ii) H}_3\text{O}^{+}]{\text{(i) B}_2\text{H}_6} \text{R–CH}_2\text{OH}

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