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Q.Three vectors a⃗\vec a, b⃗\vec b and c⃗\vec c satisfy the condition a⃗+b⃗+c⃗=0⃗\vec a + \vec b + \vec c = \vec 0. If ∣a⃗∣=1|\vec a| = 1, ∣b⃗∣=4|\vec b| = 4 and ∣c⃗∣=3|\vec c| = 3, then evaluate a⃗⋅b⃗+b⃗⋅c⃗+c⃗⋅a⃗\vec a \cdot \vec b + \vec b \cdot \vec c + \vec c \cdot \vec a.

(OR)
The two adjacent sides of a parallelogram are 2i^−4j^+5k^2\hat i - 4\hat j + 5\hat k and i^−2j^−3k^\hat i - 2\hat j - 3\hat k. Find the unit vector parallel to its diagonal. Also, find its area.
Uttarakhand UbseUttarakhand Board Intermediate (Class 12) 2025Subjective· 4mImportance★★★★★
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Concept understanding — Vector Magnitude Properties

Vector Magnitude Properties

An arrow has a direction and a length. That length — the straight-line distance from tail to tip — is the magnitude of the vector, written ∣v⃗∣|\vec{v}| or ∥v⃗∥\|\vec{v}\|. It is always non-negative and tells you how much of something there is, ignoring direction.

Definition

Magnitude is the distance from the origin to the point the vector reaches — the Pythagorean theorem in nn dimensions:

∣v⃗∣=x2+y2(2D),∣v⃗∣=x2+y2+z2(3D).|\vec{v}| = \sqrt{x^2 + y^2} \quad (\text{2D}), \qquad |\vec{v}| = \sqrt{x^2 + y^2 + z^2} \quad (\text{3D}).

The four key properties

1. Non-negativity.

∣v⃗∣≥0,∣v⃗∣=0  ⟺  v⃗=0⃗.|\vec{v}| \geq 0, \qquad |\vec{v}| = 0 \iff \vec{v} = \vec{0}.

A length is never negative, and only the zero vector has zero length.

2. Scaling.

∣kv⃗∣=∣k∣ ∣v⃗∣.|k\vec{v}| = |k|\,|\vec{v}|.

Stretching a vector by kk multiplies its length by ∣k∣|k| — the absolute value appears because a negative kk flips direction but the length still grows by ∣k∣|k|. E.g. if ∣v⃗∣=3|\vec{v}| = 3, then ∣−2v⃗∣=2×3=6|-2\vec{v}| = 2\times 3 = 6.

3. Triangle inequality.

∣u⃗+v⃗∣≤∣u⃗∣+∣v⃗∣.|\vec{u} + \vec{v}| \leq |\vec{u}| + |\vec{v}|.

The direct path is never longer than going the long way: the straight line from AA to CC is at most the distance A→B→CA \to B \to C. Equality holds only when u⃗\vec{u} and v⃗\vec{v} point in exactly the same direction.

4. Dot-product relation.

∣v⃗∣2=v⃗⋅v⃗.|\vec{v}|^2 = \vec{v} \cdot \vec{v}.

The squared length equals the vector's dot product with itself, since v⃗⋅v⃗=x2+y2+z2\vec{v}\cdot\vec{v} = x^2 + y^2 + z^2. This is the workhorse in proofs and in physics (kinetic energy 12m∣v⃗∣2\tfrac{1}{2}m|\vec{v}|^2). …

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