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Q.Find the focus of the parabola y = x² + x + 1.

West Bengal WbchseWest Bengal HS First Year (WBCHSE Class XI) Annual Examination 2018Subjective· 2mImportance★★★★★est
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Completing the square converts y=x2+x+1y=x^2+x+1 to the standard parabola form X2=4pYX^2=4pY, from which the focus follows.

Complete the square: y=x2+x+1=(x+12)2+34y=x^2+x+1=\left(x+\dfrac12\right)^2+\dfrac34, so

(x+12)2=y−34.\left(x+\dfrac12\right)^2=y-\dfrac34.

Let X=x+12, Y=y−34X=x+\dfrac12,\ Y=y-\dfrac34: this is X2=YX^2=Y, i.e. X2=4(14)YX^2=4\left(\dfrac14\right)Y, matching X2=4pYX^2=4pY with p=14p=\dfrac14.

Vertex: (X,Y)=(0,0)  ⟹  (x,y)=(−12,34)(X,Y)=(0,0)\implies (x,y)=\left(-\dfrac12,\dfrac34\right).

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