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Q.The arithmetic mean and standard deviation of 7 observations are respectively 8 and 4. If five of the observations are 2, 4, 10, 12 and 14, then find the values of the remaining two.

West Bengal WbchseWest Bengal HS First Year (WBCHSE Class XI) Annual Examination 2018Subjective· 4mImportance★★★★★est
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Use the given mean to find the sum of the two missing values, and the given SD (via ∑xi2\sum x_i^2) to find the sum of their squares; then solve the resulting quadratic.

Let the two unknown observations be x,yx,y. Total observations =7=7, mean =8=8, so total sum =7×8=56=7\times8=56.

Sum of the given five (2,4,10,12,142,4,10,12,14) =2+4+10+12+14=42=2+4+10+12+14=42.

So x+y=56−42=14x+y=56-42=14.

Using SD: SD=4  ⟹  SD=4\implies Variance =16=16. Variance formula: ∑xi27−(mean)2=16  ⟹  ∑xi27=16+64=80  ⟹  ∑xi2=560\dfrac{\sum x_i^2}{7}-(\text{mean})^2=16\implies\dfrac{\sum x_i^2}{7}=16+64=80\implies\sum x_i^2=560.

Sum of squares of the given five: 22+42+102+122+142=4+16+100+144+196=4602^2+4^2+10^2+12^2+14^2=4+16+100+144+196=460.

So x2+y2=560−460=100x^2+y^2=560-460=100.

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