Skip to content
Worked Examples · Example 3

Q.The average of 4 positive integers is 39. The highest integer is 73 and the lowest integer is 19. The difference between the remaining two integers in 18. Find the remaining integers.

Andaman Nicobar CbseNCERTSubjective· 3mImportance★★★★★est
21% · 15/70 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Find the total sum from the average, subtract the known highest and lowest, then solve a sum-and-difference pair of equations for the remaining two integers.

Average =SumNumber of terms= \dfrac{\text{Sum}}{\text{Number of terms}}; for two numbers with sum SS and difference DD (x>yx>y): x=S+D2x = \dfrac{S+D}{2}, y=S−D2y = \dfrac{S-D}{2}.

  1. Sum of the 4 positive integers == Average ×\times Count =39×4=156= 39 \times 4 = 156.
  2. Sum of the remaining two integers =156−73−19=64= 156 - 73 - 19 = 64. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.