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Chemistry · Ch 4 — Chemical Bonding and Molecular Structure

Polarity of Bonds

4.3.6

Polarity of Bonds

Polarity of Bonds

A chemical bond is formed when two atoms share a pair of electrons. But what happens when the two atoms are different? Do they pull on the shared electrons with equal strength? The answer is no — and this unequal tug-of-war is the root of bond polarity.

The Concept of Electronegativity

Electronegativity is the measure of the tendency of an atom in a molecule to attract the shared pair of electrons towards itself. It is a relative property — we compare atoms to each other. The most commonly used scale is the Pauling scale, where fluorine (the most electronegative element) is assigned a value of 4.0.

When two atoms of the same element bond (like H–H or Cl–Cl), they have identical electronegativities. The shared electron pair is pulled equally by both nuclei. The bond is non-polar — the electron cloud is symmetrically distributed, and there is no separation of charge.

When two different atoms bond, the atom with higher electronegativity pulls the shared electrons closer to itself. This creates an uneven distribution of charge: the more electronegative atom acquires a partial negative charge (δ–), and the less electronegative atom acquires a partial positive charge (δ+). The bond is now polar.

Note

The Greek letter δ (delta) denotes a partial charge — it is smaller than a full unit charge (like the +1 on Na⁺). A polar bond is a bond with a dipole — a separation of positive and negative charge centres.

Dipole Moment — A Quantitative Measure of Polarity

The extent of polarity in a bond is measured by a quantity called the dipole moment. It is defined as the product of the magnitude of the charge (q) and the distance (d) between the two charge centres.

μ=q×d\mu = q \times d

Here, μ (the Greek letter mu) is the dipole moment, q is the charge (in coulombs, C), and d is the distance (in metres, m). The dipole moment is a vector quantity — it has both magnitude and direction. By convention, the direction of the dipole moment is from the positive end towards the negative end (or, in some notations, from δ+ to δ–).

The SI unit of dipole moment is the coulomb-metre (C m). However, for molecular-scale measurements, a more convenient unit is the Debye (D), named after the physicist Peter Debye.

1 D=3.33564×10−30 C m1 \, \text{D} = 3.33564 \times 10^{-30} \, \text{C m}

For example, the dipole moment of hydrogen chloride (HCl) is 1.07 D. This tells us that the H–Cl bond is significantly polar — chlorine is more electronegative than hydrogen, so the electron pair is shifted towards Cl, giving H a δ+ and Cl a δ–.

Table 4.5Dipole Moments of Selected Molecules

The book groups the molecules by type and geometry (values in debye, D):

TypeMoleculeGeometryDipole moment, μ\mu (D)
ABHFlinear1.78
HCllinear1.07
HBrlinear0.79
HIlinear0.38
H2_2linear0
AB2_2H2_2Obent1.85
H2_2Sbent0.95
CO2_2linear0
AB3_3NH3_3trigonal pyramidal1.47
NF3_3trigonal pyramidal0.23
BF3_3trigonal planar0

The Crossed-Arrow Convention

In chemistry a bond dipole is drawn as a crossed arrow (× ⁣ ⁣− ⁣ ⁣→\times\!\!-\!\!\rightarrow) laid along the bond: the cross sits on the δ+\delta^+ end and the arrowhead points at the δ−\delta^- end, so the symbol pictures the electron shift — in HF the arrow runs from H towards F.

Watch out

The book itself flags a trap here: this chemical convention points opposite to the conventional physics definition of a dipole-moment vector, which runs from the negative charge to the positive charge. Stay consistent within one convention.

Cancellation in BeF2_2 and BF3_3

In linear BeF2_2 the two Be–F bond dipoles are equal and point in opposite directions, summing to zero. In trigonal planar BF3_3 the three B–F dipoles at 120∘120^\circ likewise add vectorially to zero. Symmetric geometry, not absent bond polarity, is what makes such molecules nonpolar.

The Marquee Comparison — NH3_3 versus NF3_3

Both molecules are trigonal pyramidal with a lone pair on nitrogen, yet μ(NH3)=4.90×10−30\mu(\text{NH}_3) = 4.90 \times 10^{-30} C m while μ(NF3)\mu(\text{NF}_3) is only 0.80×10−300.80 \times 10^{-30} C m. In NH3_3 the orbital dipole of the lone pair points the same way as the resultant of the N–H bond dipoles and reinforces it; in NF3_3 the N–F bond dipoles point toward the highly electronegative fluorines, opposing the lone-pair dipole. Partial cancellation leaves NF3_3 with the much smaller moment.

Water's Net Dipole

Bent H2_2O adds its two O–H bond dipoles at 104.5∘104.5^\circ to a resultant of 6.17×10−306.17 \times 10^{-30} C m — i.e. 1.85 D, the value in Table 4.5.

How Dipole Moment Reveals Molecular Geometry

The dipole moment is not just about individual bonds — it is a molecular property. A molecule may contain several polar bonds, yet its overall dipole moment could be zero. This happens when the bond dipoles are arranged symmetrically and cancel each other out.

Consider carbon dioxide, CO₂. Each C=O bond is polar (oxygen is more electronegative than carbon). But the molecule is linear: O=C=O. The two bond dipoles point in opposite directions — one from C to O on the left, and one from C to O on the right. They are equal in magnitude but opposite in direction, so they cancel. The net dipole moment of CO₂ is zero. This tells us that CO₂ is a linear molecule.

Now consider water, H₂O. The O–H bonds are polar. If water were linear (H–O–H), the two bond dipoles would cancel, and the net dipole moment would be zero. But experimentally, water has a dipole moment of 1.85 D. This can only happen if the molecule is bent — the two bond dipoles do not point in opposite directions; they add up vectorially to give a net dipole. The measured dipole moment confirms that water has a bent shape with a bond angle of about 104.5°.

Important

The dipole moment is a powerful experimental tool for determining molecular geometry. A non-zero dipole moment rules out a perfectly symmetric structure (like linear or tetrahedral with identical bonds). A zero dipole moment strongly suggests a symmetric arrangement where all bond dipoles cancel.

Percentage Ionic Character

No bond is 100% ionic or 100% covalent — there is always some degree of sharing. The dipole moment gives us a way to estimate how ionic a bond is.

If a bond were completely ionic (say, H⁺ Cl⁻ with full unit charges separated by the bond length), we could calculate the theoretical dipole moment using μ = q × d, where q is the charge of an electron (1.602 × 10⁻¹⁹ C) and d is the bond length. For HCl, the bond length is 1.27 Å (1.27 × 10⁻¹⁰ m). The theoretical dipole moment for a fully ionic H–Cl bond would be:

μionic=(1.602×10−19)×(1.27×10−10)=2.03×10−29 C m\mu_{\text{ionic}} = (1.602 \times 10^{-19}) \times (1.27 \times 10^{-10}) = 2.03 \times 10^{-29} \, \text{C m}

Converting to Debye:

μionic=2.03×10−293.33564×10−30≈6.09 D\mu_{\text{ionic}} = \frac{2.03 \times 10^{-29}}{3.33564 \times 10^{-30}} \approx 6.09 \, \text{D}

But the actual dipole moment of HCl is only 1.07 D. The ratio of the actual dipole moment to the theoretical ionic dipole moment gives the percentage ionic character:

Percentage ionic character=μobservedμionic×100\text{Percentage ionic character} = \frac{\mu_{\text{observed}}}{\mu_{\text{ionic}}} \times 100

For HCl:

Percentage ionic character=1.076.09×100≈17.6%\text{Percentage ionic character} = \frac{1.07}{6.09} \times 100 \approx 17.6\%

This means that the H–Cl bond is about 17.6% ionic and roughly 82% covalent. In other words, the electron pair is not fully transferred to chlorine — it is shared, but with a strong bias towards chlorine.

Watch out

The calculation above assumes that the bond length in the hypothetical ionic form is the same as in the actual molecule. This is an approximation. Also, the theoretical dipole moment for a fully ionic bond is an upper limit — real bonds always have less than 100% ionic character. …