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5.1 · Q6

Q.A fertilizer company packs the bags labelled 50 kg and claims that the mean mass of bags is 50 kg with a standard deviation 1kg. An inspector points out doubt on its weight and tests 60 bags. As a result, he finds that mean mass is 49.6 kg. Is the inspector right in his suspicions?

Andaman Nicobar CbseNCERTSubjective· 5mImportance★★★★★
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Because σ\sigma is known, a zz-test gives z=−3.10z=-3.10; ∣z∣|z| far exceeds the critical value, so we reject H0H_0 and the inspector's suspicion is justified.

z=xˉ−μσ/nz = \frac{\bar{x}-\mu}{\sigma/\sqrt{n}}

  • xˉ=49.6\bar{x}=49.6 (sample mean), μ=50\mu=50 (labelled mean), σ=1\sigma=1 (known population SD), n=60n=60.
  1. Hypotheses (inspector suspects the true mass is less than 50 kg ⇒\Rightarrow left-tailed):

H0:μ=50H1:μ<50H_0:\mu=50 \qquad H_1:\mu<50

  1. Standard error: σn=160=17.746=0.1291\dfrac{\sigma}{\sqrt{n}}=\dfrac{1}{\sqrt{60}}=\dfrac{1}{7.746}=0.1291.
  2. Test statistic:

z=49.6−500.1291=−0.40.1291=−3.098.z=\frac{49.6-50}{0.1291}=\frac{-0.4}{0.1291}=-3.098.

  1. Critical value: at α=0.05\alpha=0.05, left-tailed zcrit=−1.645z_{crit}=-1.645 (two-tailed ±1.96\pm1.96). …

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