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Q.What is the expression between pressure and kinetic energy of a gas molecule ?

Andhra Pradesh BieapBIEAP Intermediate Board (1st Year) 2018Subjective· 2mImportance★★★★★
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Pressure of an ideal gas is two-thirds of the translational kinetic energy per unit volume: P = (2/3) E.

From the kinetic theory of gases, the pressure exerted by a gas is:

P = (1/3) rho v_rms^2

where rho is the mass density of the gas and v_rms is the root-mean-square speed of the molecules.

The mean translational kinetic energy per unit volume of the gas is:

E = (1/2) rho v_rms^2

Comparing the two expressions:

P = (1/3) rho v_rms^2 = (2/3) x [(1/2) rho v_rms^2] = (2/3) E

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