Q.State Parallelogram law of vectors. Derive an expression for the magnitude and direction of the resultant vector.
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Start your 14-day free trial to unlock the full solution →Parallelogram law: two vectors as adjacent sides of a parallelogram give the resultant as the diagonal. Magnitude R = √(P² + Q² + 2PQ cosθ); direction tan α = Q sinθ / (P + Q cosθ).
Statement of the Parallelogram Law of Vectors: If two vectors acting simultaneously at a point are represented in both magnitude and direction by the two adjacent sides of a parallelogram drawn from that point, then their resultant is represented in magnitude and direction by the diagonal of the parallelogram passing through that same point.
Derivation of magnitude:
Let two vectors P and Q be represented by the adjacent sides OA and OB of a parallelogram OACB, with angle θ between them. The diagonal OC represents the resultant R.
Drop a perpendicular from C to the extension of OA, meeting it at D.
In the right triangle OCD:
OC² = OD² + CD²
OC² = (OA + AD)² + CD²
From triangle ACD, with AC = Q and angle CAD = θ:
AD = Q cos θ and CD = Q sin θ
Also OA = P. Substituting:
R² = (P + Q cos θ)² + (Q sin θ)²
R² = P² + 2PQ cos θ + Q² cos²θ + Q² sin²θ
R² = P² + Q² (cos²θ + sin²θ) + 2PQ cos θ
R² = P² + Q² + 2PQ cos θ
Therefore, magnitude of the resultant: …
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