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Q.State Parallelogram law of vectors. Derive an expression for the magnitude and direction of the resultant vector.

Andhra Pradesh BieapBIEAP Intermediate Board (1st Year) 2022Subjective· 4mImportance★★★★★
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Parallelogram law: two vectors as adjacent sides of a parallelogram give the resultant as the diagonal. Magnitude R = √(P² + Q² + 2PQ cosθ); direction tan α = Q sinθ / (P + Q cosθ).

Statement of the Parallelogram Law of Vectors: If two vectors acting simultaneously at a point are represented in both magnitude and direction by the two adjacent sides of a parallelogram drawn from that point, then their resultant is represented in magnitude and direction by the diagonal of the parallelogram passing through that same point.

Derivation of magnitude:

Let two vectors P and Q be represented by the adjacent sides OA and OB of a parallelogram OACB, with angle θ between them. The diagonal OC represents the resultant R.

Drop a perpendicular from C to the extension of OA, meeting it at D.

In the right triangle OCD:

OC² = OD² + CD²

OC² = (OA + AD)² + CD²

From triangle ACD, with AC = Q and angle CAD = θ:

AD = Q cos θ and CD = Q sin θ

Also OA = P. Substituting:

R² = (P + Q cos θ)² + (Q sin θ)²

R² = P² + 2PQ cos θ + Q² cos²θ + Q² sin²θ

R² = P² + Q² (cos²θ + sin²θ) + 2PQ cos θ

R² = P² + Q² + 2PQ cos θ

Therefore, magnitude of the resultant: …

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