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Worked Examples · Example 4

Q.The output (in tonnes) of a small factory over 5 consecutive days is: 2, 4, 6, 8, 10. Calculate the Standard Deviation by the direct (actual mean) method.

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Step 1 — Arithmetic mean.

Xˉ=2+4+6+8+105=305=6\bar{X} = \frac{2+4+6+8+10}{5} = \frac{30}{5} = 6

Step 2 — Deviations and squared deviations from the mean.

(2−6)=−4, (4−6)=−2, (6−6)=0, (8−6)=2, (10−6)=4(2-6)=-4,\ (4-6)=-2,\ (6-6)=0,\ (8-6)=2,\ (10-6)=4

(−4)2=16, (−2)2=4, 02=0, 22=4, 42=16(-4)^2=16,\ (-2)^2=4,\ 0^2=0,\ 2^2=4,\ 4^2=16

Σ(X−Xˉ)2=16+4+0+4+16=40\Sigma(X-\bar{X})^2 = 16+4+0+4+16 = 40

Step 3 — Standard Deviation. …

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