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Worked Examples · Example 34

Q.Find the number of ways in which 8 different beads can be arranged to form a necklace.

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8 different beads arranged into a necklace: (8−1)!2=2520\dfrac{(8-1)!}{2}=2520 distinct necklaces.

Necklace arrangements of nn distinct beads (rotations AND reflections/flips treated as identical) =(n−1)!2=\dfrac{(n-1)!}{2}.

  1. n=8n=8 distinct beads.
  2. Circular (rotation-only) arrangements: (8−1)!=7!=5040(8-1)!=7!=5040. …

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