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Worked Examples · Example 5

Q.If 19!+110!=x11!\dfrac{1}{9!} + \dfrac{1}{10!} = \dfrac{x}{11!}, find xx

Arunachal CbseNCERTSubjective· 2mImportance★★★★★est
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Put both fractions over the common denominator 10!10!, then scale up to denominator 11!11! to read off xx.

10!=10×9!10! = 10\times9! and 11!=11×10!11! = 11\times10!, so factorials with consecutive index differ by that multiplying integer.

  1. Write 19!\dfrac{1}{9!} with denominator 10!10!: since 10!=10×9!10! = 10\times9!, 19!=1010!\dfrac{1}{9!} = \dfrac{10}{10!}.
  2. So 19!+110!=1010!+110!=1110!\dfrac{1}{9!}+\dfrac{1}{10!} = \dfrac{10}{10!}+\dfrac{1}{10!} = \dfrac{11}{10!}. …

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