Q.Explain why the following two structures, I and II, cannot be the major contributors to the real structure of CH₃COOCH₃ (methyl acetate).
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Start your 14-day free trial to unlock the full solution →The two structures the textbook prints for methyl acetate both involve charge separation, which costs energy and makes any contributor minor; structure I is doubly penalised because its central carbon is left with an incomplete octet (six electrons).
The major contributor for methyl acetate is the familiar neutral ester structure:
Every atom is neutral, the carbonyl carbon has four bonds (a full octet), and both oxygens keep two lone pairs. The question asks why the two charge-separated structures printed in the textbook cannot be major contributors.
Structure I:
The carbonyl π pair has moved entirely onto the top oxygen. Two things go wrong at once:
- Charge separation. A negative charge on the former carbonyl oxygen and a positive charge on carbon must be held apart against their attraction — that always raises the energy relative to the neutral structure.
- An incomplete octet on carbon. The central carbon now has just three σ bonds and no π bond — six valence electrons. A second-period atom with a sextet is a high-energy arrangement (it is essentially a carbocation centre).
Structure II: …
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