Q.Find out the oxidation number of chlorine in the following compounds and arrange them in increasing order of oxidation number of chlorine.
NaClO4, NaClO3, NaClO, KClO2, Cl2O7, ClO3, Cl2O, NaCl, Cl2, ClO2.
Which oxidation state is not present in any of the above compounds?
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Start your 14-day free trial to unlock the full solution →The oxidation number of chlorine is determined by assigning known oxidation states to other atoms and solving for Cl. The increasing order of oxidation numbers is: NaCl, Cl₂, Cl₂O, NaClO, KClO₂, ClO₂, NaClO₃, ClO₃, NaClO₄, Cl₂O₇. The missing oxidation state is +2.
The core idea is simple: oxidation numbers are a bookkeeping tool that tracks electron ownership in compounds. For chlorine, we use the rule that oxygen is almost always -2 (except in peroxides, which aren't here), and alkali metals like Na and K are always +1. The sum of oxidation numbers in a neutral compound is zero; in a polyatomic ion, it equals the ion's charge.
Let's work through each compound step by step.
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NaCl — Sodium is +1, so chlorine must be -1 to balance. This is the most reduced form of chlorine.
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Cl₂ — In a diatomic element, each atom has oxidation number 0 by definition.
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Cl₂O — Oxygen is -2. Two chlorines share the +2 total, so each Cl is +1.
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NaClO — Na is +1, O is -2. Let Cl be : . So Cl is +1 here too.
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ClO₂ — Chlorine dioxide is a neutral radical molecule; for oxidation-number purposes it is still treated as a whole with net charge zero. O is -2 each, so two oxygens give -4. Then . So Cl is +4.
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KClO₂ — K is +1, each O is -2 (two oxygens = -4). Then . So Cl is +3.
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NaClO₃ — Na is +1, three O's give -6. Then . So Cl is +5.
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ClO₃ — This is the chlorate radical (neutral). Three O's give -6, so . So Cl is +6.
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NaClO₄ — Na is +1, four O's give -8. Then . So Cl is +7.
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Cl₂O₇ — Seven O's give -14 total. Two chlorines share +14, so each Cl is +7.
A common mistake is to treat ClO₂ or ClO₃ as ions. They are neutral molecules (radicals), so the sum of oxidation numbers is zero, not -1 or -2. Always check the formula carefully.
Now arrange them in increasing order of oxidation number:
| Compound | Oxidation number of Cl |
|---|---|
| NaCl | -1 |
| Cl₂ | 0 |
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