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NCERT Exemplar · Q41

Q.The sum of probabilities of two students getting distinction in their final examinations is 1.21.2.

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The sum of probabilities of two separate events can exceed 11, provided each individual probability is between 00 and 11. The given sum of 1.21.2 is therefore entirely possible.

Concept and Intuition: Understanding Probability Sums

Probability is a measure of the likelihood of an event occurring, always ranging from 00 (impossible) to 11 (certain). For any single event, its probability P(E)P(E) must satisfy 0≤P(E)≤10 \le P(E) \le 1. This is a fundamental axiom of probability theory.

However, this rule applies to individual events. When we consider the sum of probabilities of multiple distinct events, say P(A)+P(B)P(A) + P(B), this sum is not necessarily bound by 11. The sum can indeed be greater than 11. This is because events AA and BB might not be mutually exclusive (they can both happen) and they are not necessarily exhaustive (they don't cover all possibilities).

For example, consider the probability of rain today (P(R)P(R)) and the probability of a sunny day tomorrow (P(S)P(S)). Both P(R)P(R) and P(S)P(S) must be between 00 and 11. If P(R)=0.8P(R) = 0.8 and P(S)=0.7P(S) = 0.7, then P(R)+P(S)=1.5P(R) + P(S) = 1.5. This is a perfectly valid scenario, as long as P(R)P(R) and P(S)P(S) individually respect the 0≤P(E)≤10 \le P(E) \le 1 rule. The problem given is a direct application of this concept.

  1. Define the Events and Given Information Let P(D1)P(D_1) be the probability that the first student gets a distinction in their final examinations. Let P(D2)P(D_2) be the probability that the second student gets a distinction in their final examinations. The problem states that the sum of these probabilities is 1.21.2.

P(D1)+P(D2)=1.2P(D_1) + P(D_2) = 1.2

  1. Recall the Fundamental Axiom of Probability For any event EE, its probability P(E)P(E) must satisfy:

0≤P(E)≤10 \le P(E) \le 1

This means that the probability of the first student getting a distinction must be between $0$ and $1$, and similarly for the second student:

0≤P(D1)≤10 \le P(D_1) \le 1

0≤P(D2)≤10 \le P(D_2) \le 1

  1. Analyze the Sum of Probabilities The sum of probabilities of two separate events, P(D1)+P(D2)P(D_1) + P(D_2), is not constrained to be less than or equal to 11. This constraint applies to the probability of a single event or the sum of probabilities of mutually exclusive and exhaustive events within a sample space. As long as the individual probabilities P(D1)P(D_1) and P(D2)P(D_2) are valid (i.e., between 00 and 11), their sum can exceed 11. …

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