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NCERT Exemplar · Q44

Q.Equations of the lines through the point (3,2)(3,2) and making an angle of 45∘45^\circ with the line x−2y=3x-2y=3 are ____.

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The key idea is to use the slope formula for the angle between two lines. The slopes of the required lines are found by solving tan⁡45∘=∣m−121+12m∣\tan 45^\circ = \left| \frac{m - \frac12}{1 + \frac12 m} \right|, giving m=3m = 3 and m=−13m = -\frac13. The equations through (3,2)(3,2) are 3x−y=73x - y = 7 and x+3y=9x + 3y = 9.


Concept and Intuition

When a problem says "a line makes an angle of 45∘45^\circ with another line," it is always about the acute angle between their directions — that is, the angle between their slopes. The formula connecting the angle θ\theta between two lines with slopes m1m_1 and m2m_2 is:

tan⁡θ=∣m1−m21+m1m2∣\tan \theta = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right|

Here, one line is given: x−2y=3x - 2y = 3. Its slope is m1=12m_1 = \frac12. We want lines through (3,2)(3,2) whose slope mm makes a 45∘45^\circ angle with this line. So we set tan⁡45∘=1\tan 45^\circ = 1 and solve for mm.

Because the formula uses absolute value, we get two possible slopes — one steeper, one shallower — corresponding to the two lines that can be drawn through the point at exactly 45∘45^\circ on either side of the given line.


Step-by-step solution

1. Find the slope of the given line.

Rewrite x−2y=3x - 2y = 3 as y=12x−32y = \frac12 x - \frac32.

So the slope is m1=12m_1 = \frac12.

2. Write the slope of the unknown line.

Let the required line through (3,2)(3,2) have slope mm. Its equation will be y−2=m(x−3)y - 2 = m(x - 3).

3. Apply the angle-between-lines formula.

We want θ=45∘\theta = 45^\circ, so tan⁡45∘=1\tan 45^\circ = 1.

Thus:

1=∣m−121+12m∣1 = \left| \frac{m - \frac12}{1 + \frac12 m} \right|

4. Remove the absolute value — two cases.

Case 1:

m−121+12m=1\frac{m - \frac12}{1 + \frac12 m} = 1

Multiply through: m−12=1+12mm - \frac12 = 1 + \frac12 m

⇒m−12m=1+12\Rightarrow m - \frac12 m = 1 + \frac12

⇒12m=32\Rightarrow \frac12 m = \frac32

⇒m=3\Rightarrow m = 3

Case 2:

m−121+12m=−1\frac{m - \frac12}{1 + \frac12 m} = -1

Multiply: m−12=−1−12mm - \frac12 = -1 - \frac12 m

⇒m+12m=−1+12\Rightarrow m + \frac12 m = -1 + \frac12

⇒32m=−12\Rightarrow \frac32 m = -\frac12

⇒m=−13\Rightarrow m = -\frac13 …

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