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Exercise 1 · Q1

Q.Determine the order and degree (if defined) of the differential equation: xdydx+2y=x2x\frac{dy}{dx}+2y=x^2, x≠0x\ne 0

Arunachal CbseNCERTSubjective· 2mImportance★★★★★
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✓ Free question

The highest derivative is dydx\dfrac{dy}{dx} (first order), appearing to the first power, so the order is 11 and the degree is 11.

Order = order of the highest derivative present. Degree = power of the highest-order derivative after the equation is made a polynomial in its derivatives (free of radicals/fractions in derivatives).

Given: xdydx+2y=x2, x≠0x\dfrac{dy}{dx}+2y=x^2,\ x\ne 0.

  1. The highest derivative present is dydx\dfrac{dy}{dx} → order =1=1.
  2. The equation is already a polynomial in dydx\dfrac{dy}{dx}, and dydx\dfrac{dy}{dx} occurs to the first power → degree =1=1.
✓Final answer

Order =1=1, degree =1=1.

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