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Worked Examples · Example 4

Q.How much money is needed to endure a series of lectures costing ₹2500 at the beginning of each year indefinitely, if money is worth 3% compounded annually?

Arunachal CbseNCERTSubjective· 3mImportance★★★★★
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The key idea is to treat the series of payments as a perpetuity due — payments at the start of each year forever. The present value is the amount needed today, which is ₹85,833.33.

To understand why this works, think about what "money worth 3% compounded annually" means. It means that if you invest a sum today at 3% per year, the interest earned each year is exactly enough to cover the ₹2500 payment at the start of that year, without ever touching the principal. The trick is that the first payment happens immediately (at the beginning of year 1), so you need to have that ₹2500 ready right now, plus enough principal left over to generate the subsequent payments forever.

The standard formula for a perpetuity (payments at the end of each period) is PV=CrPV = \frac{C}{r}, where CC is the annual payment and rr is the interest rate. But here, payments are at the beginning — that's a perpetuity due. The adjustment is simple: each payment is moved one year earlier, so the present value is larger by a factor of (1+r)(1+r).

Let's work through it step by step.

  1. Identify the variables.

    The annual payment at the start of each year is C=₹2500C = ₹2500. The annual interest rate is r=3%=0.03r = 3\% = 0.03.

  2. Recall the perpetuity due formula.

    For a perpetuity due (payments at the beginning of each period), the present value is:

PVdue=C+CrPV_{\text{due}} = C + \frac{C}{r}

Why? Because the first payment of CC is made immediately (so its present value is just CC), and the remaining infinite stream of payments (at years 1, 2, 3, …) forms an ordinary perpetuity. Deriving the present value of the full combined stream carefully:

›Proof

Derivation of perpetuity due formula:

The present value of a perpetuity due is:

PV=C+C1+r+C(1+r)2+C(1+r)3+⋯PV = C + \frac{C}{1+r} + \frac{C}{(1+r)^2} + \frac{C}{(1+r)^3} + \cdots

This is a geometric series with first term CC and common ratio 11+r\frac{1}{1+r}. Sum to infinity:

PV=C1−11+r=Cr1+r=C⋅1+rrPV = \frac{C}{1 - \frac{1}{1+r}} = \frac{C}{\frac{r}{1+r}} = C \cdot \frac{1+r}{r}

So the formula is:

PVdue=C⋅1+rrPV_{\text{due}} = C \cdot \frac{1+r}{r}

Alternatively, you can think: PVdue=(1+r)×PVordinaryPV_{\text{due}} = (1+r) \times PV_{\text{ordinary}}, where PVordinary=CrPV_{\text{ordinary}} = \frac{C}{r}.

So the correct formula is PV=C⋅1+rrPV = C \cdot \frac{1+r}{r}.

  1. Plug in the numbers. PV=2500×1+0.030.03=2500×1.030.03PV = 2500 \times \frac{1 + 0.03}{0.03} = 2500 \times \frac{1.03}{0.03} …

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