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Worked Examples · Example 13

Q.Find all the positive integers less than 30 forming the equivalence class of 5 for modulo 7.

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The equivalence class of 55 modulo 77 collects all integers of the form 5+7k5+7k; those below 3030 are 5,12,19,265, 12, 19, 26.

[5]7={ x:x≡5(mod7) }={ 5+7k:k=0,1,2,… }[5]_7 = \{\,x : x\equiv 5\pmod 7\,\} = \{\,5 + 7k : k=0,1,2,\dots\,\}

where kk is a non-negative integer, so successive members differ by the modulus 77.

  1. Start at the representative 55 and add 77 repeatedly:

k=0: 5k=0:\ 5

k=1: 5+7=12k=1:\ 5+7 = 12

k=2: 12+7=19k=2:\ 12+7 = 19

k=3: 19+7=26k=3:\ 19+7 = 26

  1. Next term exceeds the limit: k=4: 26+7=33>30 (reject)k=4:\ 26+7 = 33 > 30\ \text{(reject)} …

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