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Q.Given that xx, yy and bb are real numbers and x<yx < y, b<0b < 0, then (A) xb<yb\dfrac{x}{b} < \dfrac{y}{b}
(B) xb≤yb\dfrac{x}{b} \le \dfrac{y}{b}
(C) xb>yb\dfrac{x}{b} > \dfrac{y}{b}
(D) xb≥yb\dfrac{x}{b} \ge \dfrac{y}{b}

Assam AhsecAHSEC Higher Secondary (HS) 1st Year Examination 2026MCQ· 1mImportance★★★★★
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Dividing x<yx<y by the negative number bb flips the sign: xb>yb\frac{x}{b} > \frac{y}{b}.

A key rule: multiplying or dividing an inequality by a negative number reverses the inequality.

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