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Exercise 2.2 · Q1

Q.Let A={1,2,3,…,14}A = \{1, 2, 3, \ldots, 14\}. Define a relation RR from AA to AA by R={(x,y):3x−y=0, where x,y∈A}R = \{(x, y) : 3x - y = 0,\ \text{where}\ x, y \in A\}. Write down its domain, codomain and range.

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The relation RR is defined by 3x−y=03x - y = 0, so y=3xy = 3x. Only pairs where both xx and 3x3x lie in A={1,2,…,14}A = \{1,2,\dots,14\} are included. The domain is {1,2,3,4}\{1,2,3,4\}, the codomain is AA, and the range is {3,6,9,12}\{3,6,9,12\}.

The key idea is to see the relation as a mapping: each xx in AA is linked to exactly one yy in AA through the equation y=3xy = 3x. But not every xx in AA will produce a yy that stays inside AA — and that's what decides the domain and range.

Think of drawing an arrow diagram. You have set AA on the left and the same set AA on the right. For each xx in the left set, you check if 3x3x is a number in the right set. If yes, you draw an arrow from xx to 3x3x. The domain is the set of all left-side numbers that have an arrow leaving them. The range is the set of all right-side numbers that have an arrow arriving at them. The codomain is simply the entire right-side set — whether or not any arrow reaches it.

Now let's work through it.

  1. Rewrite the condition.

    The relation is R={(x,y):3x−y=0,x,y∈A}R = \{(x, y) : 3x - y = 0, x, y \in A\}.

    This simplifies to y=3xy = 3x. So for each xx, the corresponding yy is forced to be 3x3x.

  2. Find which xx values are allowed.

    Since xx must be in A={1,2,3,…,14}A = \{1, 2, 3, \ldots, 14\}, and y=3xy = 3x must also be in AA, we need 3x≤143x \leq 14.

    Solve 3x≤14  ⟹  x≤143≈4.673x \leq 14 \implies x \leq \frac{14}{3} \approx 4.67.

    Since xx is a positive integer, the possible xx values are 1,2,3,41, 2, 3, 4.

  3. List the ordered pairs.

    For x=1x = 1, y=3y = 3 → (1,3)(1,3)

    For x=2x = 2, y=6y = 6 → (2,6)(2,6)

    For x=3x = 3, y=9y = 9 → (3,9)(3,9)

    For x=4x = 4, y=12y = 12 → (4,12)(4,12)

    For x=5x = 5, y=15y = 15 — but 15∉A15 \notin A, so no pair.

    So R={(1,3),(2,6),(3,9),(4,12)}R = \{(1,3), (2,6), (3,9), (4,12)\}.

  4. Identify the domain.

    The domain is the set of all first elements in the ordered pairs.

    Domain ={1,2,3,4}= \{1, 2, 3, 4\}.

  5. Identify the codomain.

    The codomain is given as the set to which yy belongs — here it's AA itself.

    Codomain ={1,2,3,…,14}= \{1, 2, 3, \ldots, 14\}.

  6. Identify the range.

    The range is the set of all second elements that actually appear in the relation.

    Range ={3,6,9,12}= \{3, 6, 9, 12\}.

Watch out

A common mistake is to think the domain is all xx from 11 to 1414 because the relation is defined "from AA to AA". But the condition 3x−y=03x - y = 0 restricts which xx actually produce a valid yy inside AA. Always check the condition.

Tip

Notice that the range is a subset of the codomain, and here it's a proper subset. The codomain is the "promised" set; the range is what actually gets used.

✓Final answer

The domain is {1,2,3,4}\{1, 2, 3, 4\}, the codomain is {1,2,3,…,14}\{1, 2, 3, \ldots, 14\}, and the range is {3,6,9,12}\{3, 6, 9, 12\}.

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