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Q.Find the mean deviation from the mean of the frequency distribution given below: Class: 0-100, 100-200, 200-300, 300-400, 400-500, 500-600, 600-700, 700-800; Frequency: 4, 8, 9, 10, 7, 5, 4, 3. OR The mean of 5 observations is 4.4 and their variance is 8.24. If three of the observations are 1, 2 and 6, then find the other two observations.
Assam AhsecAHSEC Higher Secondary (HS) 1st Year Examination 2019Subjective· 6mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →Compute the mean of the distribution, then the mean of the absolute deviations from it. [OR alternative: use the mean and variance formulas to set up and solve a pair of equations for the two unknown observations.]
Main question. Classes (mid-points ) and frequencies :
| Class | |||||
|---|---|---|---|---|---|
| 0–100 | 50 | 4 | 200 | 308 | 1232 |
| 100–200 | 150 | 8 | 1200 | 208 | 1664 |
| 200–300 | 250 | 9 | 2250 | 108 | 972 |
| 300–400 | 350 | 10 | 3500 | 8 | 80 |
| 400–500 | 450 | 7 | 3150 | 92 | 644 |
| 500–600 | 550 | 5 | 2750 | 192 | 960 |
| 600–700 | 650 | 4 | 2600 | 292 | 1168 |
| 700–800 | 750 | 3 | 2250 | 392 | 1176 |
, .
Mean: .
.
Mean deviation about the mean .
OR (alternative question): Mean of 5 observations is , variance is ; three of them are . Find the other two.
Let the other two be . Sum of all 5 . Sum of known three , so: …
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