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Q.Find the mean deviation about the mean for the following data: 6,7,10,12,13,4,8,126, 7, 10, 12, 13, 4, 8, 12

Assam AhsecAHSEC Higher Secondary (HS) 1st Year Examination 2025Subjective· 2mImportance★★★★★
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Mean deviation about the mean =2.75=2.75.

Step 1 — Mean. xˉ=6+7+10+12+13+4+8+128=728=9.\bar x=\frac{6+7+10+12+13+4+8+12}{8}=\frac{72}{8}=9.

Step 2 — Absolute deviations ∣xi−9∣|x_i-9|: 3,2,1,3,4,5,1,3.3,2,1,3,4,5,1,3.

Step 3 — Sum and divide. ∑∣xi−9∣=3+2+1+3+4+5+1+3=22\sum|x_i-9|=3+2+1+3+4+5+1+3=22, so

M.D.(xˉ)=228=2.75.\text{M.D.}(\bar x)=\frac{22}{8}=2.75.

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