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Q.A magnetic dipole is oscillating in a magnetic field obeying the following expression: d²θ/dt² = -(mB/I)θ. What is the time period of oscillation and mention the nature of oscillation?

Assam AhsecAHSEC Higher Secondary (HS) Final Examination 2019Subjective· 2mImportance★★★★★
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The given equation is the standard SHM form θ¨=−ω2θ\ddot\theta = -\omega^2\theta, giving T=2πI/mBT = 2\pi\sqrt{I/mB} and simple harmonic oscillation.

Compare the given equation d2θdt2=−mBIθ\dfrac{d^2\theta}{dt^2} = -\dfrac{mB}{I}\theta with the standard differential equation of angular SHM, d2θdt2=−ω2θ\dfrac{d^2\theta}{dt^2} = -\omega^2\theta. Matching terms:

ω2=mBI⇒ω=mBI\omega^2 = \dfrac{mB}{I} \quad\Rightarrow\quad \omega = \sqrt{\dfrac{mB}{I}}

The time period is T=2πωT = \dfrac{2\pi}{\omega}, so:

T=2πImBT = 2\pi\sqrt{\dfrac{I}{mB}}

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