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Q.A bar magnet of mass 120 g in the form of a rectangular parallelopiped, has dimensions l = 40 mm, b = 10 mm and h = 80 mm, with its dimension 'h' vertical, the magnet performs angular oscillations in the plane of the magnetic field with period π\pi seconds. If the magnetic moment is 3.4 A m², determine the influencing magnetic field.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2023Subjective· 2mImportance★★★★★
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Angular oscillation of a bar magnet in a field gives BB from T=2πI/(MB)T=2\pi\sqrt{I/(MB)}.

The magnet oscillates about the vertical axis (through its centre, along hh), so its moment of inertia for this rotation is that of a rectangular lamina about an axis perpendicular to the ll–bb plane through its centre:

I=m(l2+b2)12I = \frac{m(l^2+b^2)}{12}

With m=0.12m=0.12 kg, l=0.04l=0.04 m, b=0.01b=0.01 m:

I=0.12×(0.0016+0.0001)12=0.12×0.001712=1.7×10−5 kg m2I = \frac{0.12\times(0.0016+0.0001)}{12} = \frac{0.12\times0.0017}{12} = 1.7\times10^{-5}\ \text{kg m}^2

The period of angular oscillation of a magnet of moment MM in field BB is …

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