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Worked Examples · Example 1

Q.Calculate the range and quartile deviation (Q.D.) of the following observations: 20, 25, 29, 30, 35, 39, 41, 48, 51, 60 and 70.

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Range =50= 50; Q1=29Q_1 = 29, Q3=51Q_3 = 51, so Q.D.=11Q.D. = 11.

Step 1 — Range. The largest value is L=70L = 70 and the smallest is S=20S = 20, so

R=L−S=70−20=50R = L - S = 70 - 20 = 50

Step 2 — Locate the quartiles. This is an individual (ungrouped) series with n=11n = 11, and the values are already in ascending order.

Q1Q_1 is the size of the n+14th=11+14=3rd\dfrac{n+1}{4}\text{th} = \dfrac{11+1}{4} = 3\text{rd} value. The 3rd value is 29, so Q1=29Q_1 = 29.

Q3Q_3 is the size of the 3(n+1)4th=3×124=9th\dfrac{3(n+1)}{4}\text{th} = \dfrac{3 \times 12}{4} = 9\text{th} value. The 9th value is 51, so Q3=51Q_3 = 51.

Step 3 — Quartile deviation.

Q.D.=Q3−Q12=51−292=222=11Q.D. = \dfrac{Q_3 - Q_1}{2} = \dfrac{51 - 29}{2} = \dfrac{22}{2} = 11

So the range of the data is 50 and the quartile deviation is 11. (Note that Q.D. is the average distance of the two quartiles from the median.)

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