Q.Let us compute the standard deviation of the hight of nine students that we used while calculating Mean. The Mean (x̄) was calculated to be 101.33 cm.
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Start your 14-day free trial to unlock the full solution →Standard deviation (σ) measures how far values typically sit from the mean. Recipe: subtract the mean from each value, square, average the squares (that is the variance), take the square root. For the nine heights (mean 101.33 cm) this gives σ = √(938/9) ≈ 10.21 cm.
Why squares?
Deviations from the mean always sum to (nearly) zero — positives cancel negatives — so averaging them directly tells us nothing. Squaring makes every deviation positive; taking the square root at the end returns the answer to the original unit (cm).
Step-by-step table
Mean x̄ = 912 / 9 = 101.33 cm (from the earlier example). For each height x, compute the deviation (x − x̄) and its square:
| x (cm) | x − x̄ | (x − x̄)² |
|---|---|---|
| 90 | −11.33 | 128.44 |
| 102 | 0.67 | 0.44 |
| 110 | 8.67 | 75.11 |
| 115 | 13.67 | 186.78 |
| 85 | −16.33 | 266.78 |
| 90 | −11.33 | 128.44 |
| 100 | −1.33 | 1.78 |
| 110 | 8.67 | 75.11 |
| 110 | 8.67 | 75.11 |
| Sum | ≈ 0 | 938.00 |
(The deviation column summing to ~0 is a good self-check that the mean was right.)
Variance = 938 / 9 ≈ 104.22 cm²
Standard deviation σ = √104.22 ≈ 10.21 cm
Interpretation: heights typically differ from the class mean by about 10 cm — consistent with the data, where values run from 16.33 below the mean (85) to 13.67 above it (115).
In Python
import statistics
heights = [90, 102, 110, 115, 85, 90, 100, 110, 110]
mean = statistics.mean(heights)
sq_dev = [(x - mean) ** 2 for x in heights]
variance = sum(sq_dev) / len(heights)
sigma = variance ** 0.5 …
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