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Q.3 mL of oxygen were collected at 6°C and 758 mm pressure. Calculate its volume at N.T.P.

Bihar BsebBihar Board Intermediate 1st Year 2023Subjective· 5mImportance★★★★★
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The volume at N.T.P. is about 2.93 mL.

Use the combined gas law:

P1V1/T1 = P2V2/T2

Given (initial) conditions:

V1 = 3 mL, T1 = 6 + 273 = 279 K, P1 = 758 mm Hg

N.T.P. (final) conditions: T2 = 273 K, P2 = 760 mm Hg, V2 = ?

Rearrange for V2:

V2 = V1 x (P1/P2) x (T2/T1)

V2 = 3 x (758/760) x (273/279)

V2 = 3 x 0.99737 x 0.97849

V2 = 3 x 0.97591

V2 = 2.93 mL

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