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Exercises · 5.13

Q.Calculate the total number of electrons present in 1.4 g of dinitrogen gas.

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Step 1 – Moles of N2_2

n(N2)=1.4 g28 g mol−1=0.05 moln(\text{N}_2) = \frac{1.4\ \text{g}}{28\ \text{g mol}^{-1}} = 0.05\ \text{mol}

Step 2 – Number of N2_2 molecules (Avogadro's number)

N(N2)=0.05×6.022×1023=3.011×1022 moleculesN(\text{N}_2) = 0.05 \times 6.022\times10^{23} = 3.011\times10^{22}\ \text{molecules}

Step 3 – Electrons per N2_2 molecule

Nitrogen has atomic number Z=7Z=7, so each N atom has 7 electrons; N2_2 has: …

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