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Worked Examples · Example 18

Q.Compute the derivative of f(x)=sin⁡2xf(x) = \sin^2 x.

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Write sin⁡2x=sin⁡x⋅sin⁡x\sin^2 x = \sin x\cdot\sin x and apply the product rule of differentiation. This gives f′(x)=2sin⁡xcos⁡xf'(x)=2\sin x\cos x, which simplifies to sin⁡2x\sin 2x.

Why the product rule is the natural Class 11 tool

The expression sin⁡2x\sin^2 x means (sin⁡x)2(\sin x)^2, i.e. sin⁡x\sin x multiplied by itself. The product rule tells us how to differentiate a product of two functions, so it applies directly — no higher-class machinery is needed.

Product rule: if f(x)=u(x) v(x)f(x)=u(x)\,v(x), then f′(x)=u′(x) v(x)+u(x) v′(x)f'(x)=u'(x)\,v(x)+u(x)\,v'(x).

We also use the standard derivative ddx(sin⁡x)=cos⁡x\dfrac{d}{dx}(\sin x)=\cos x.


Step-by-step computation

Step 1 — Write the function as a product.

f(x)=sin⁡2x=sin⁡x⋅sin⁡x.f(x)=\sin^2 x = \sin x\cdot\sin x.

So take u=sin⁡xu=\sin x and v=sin⁡xv=\sin x.

Step 2 — Differentiate each factor.

u′=cos⁡x,v′=cos⁡x.u'=\cos x,\qquad v'=\cos x.

Step 3 — Apply the product rule. …

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