Skip to content
Exercises · Q12

Q.Prove the following by using the principle of mathematical induction for all n∈Nn \in N: a+ar+ar2+…+arn−1=a(rn−1)r−1a + ar + ar^2 + \ldots + ar^{n-1} = \dfrac{a(r^n - 1)}{r - 1}

Bihar BsebTextbookSubjectiveImportance★★★★★est
63% · 20/32 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Let P(n)P(n) be the statement (for fixed a≠0a\ne0, r≠1r\ne1)

a+ar+ar2+…+arn−1=a(rn−1)r−1.a+ar+ar^2+\ldots+ar^{n-1}=\frac{a(r^n-1)}{r-1}.

Base case: For n=1n=1, LHS =a=a, and

RHS=a(r−1)r−1=a.\text{RHS}=\frac{a(r-1)}{r-1}=a.

So P(1)P(1) is true.

Inductive step: Assume P(k)P(k) is true for some k≥1k\ge1:

a+ar+…+ark−1=a(rk−1)r−1.(Induction Hypothesis)a+ar+\ldots+ar^{k-1}=\frac{a(r^k-1)}{r-1}. \qquad \text{(Induction Hypothesis)}

We must show a+ar+…+ark−1+ark=a(rk+1−1)r−1a+ar+\ldots+ar^{k-1}+ar^k=\dfrac{a(r^{k+1}-1)}{r-1}.

Adding the next term arkar^k to both sides of the hypothesis: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.