Skip to content
Question of 114

Q.The first three terms of the sequence tn=4n2+3t_n = 4n^2 + 3 is

(a) 6, 19, 88
(b) 7, 19, 39
(c) 8, 19, 39
(d) None
Bihar BsebBihar Board Intermediate 1st Year 2022MCQ· 1mImportance★★★★★
0% · 0/114 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

First three terms of tn=4n2+3t_n=4n^2+3 are 7,19,397,19,39.

t1=4(1)2+3=7t_1=4(1)^2+3=7, t2=4(4)+3=19t_2=4(4)+3=19, t3=4(9)+3=39t_3=4(9)+3=39.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.