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Q.If an=n⋅n2+54a_n = n \cdot \dfrac{n^2 + 5}{4}, find the first five terms.

Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2022Subjective· 2mImportance★★★★★
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Substituting n=1n=1 through 55 into an=n⋅n2+54a_n = n\cdot\frac{n^2+5}{4} gives the first five terms.

Given an=n⋅n2+54a_n = n\cdot\dfrac{n^2+5}{4}.

a1=1⋅1+54=64=32a_1 = 1\cdot\dfrac{1+5}{4} = \dfrac{6}{4} = \dfrac{3}{2}

a2=2⋅4+54=184=92a_2 = 2\cdot\dfrac{4+5}{4} = \dfrac{18}{4} = \dfrac{9}{2}

a3=3⋅9+54=424=212a_3 = 3\cdot\dfrac{9+5}{4} = \dfrac{42}{4} = \dfrac{21}{2}

a4=4⋅16+54=844=21a_4 = 4\cdot\dfrac{16+5}{4} = \dfrac{84}{4} = 21

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