Q.The relation between the coefficient of volume expansion (αv) and the coefficient of linear expansion (αl) is
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Thermal Expansion Coefficient: From Intuition to Precision
The Intuition: What Happens When Things Get Hot?
Think about a metal railway track on a summer day. The track is laid in sections with small gaps between them. On a hot afternoon, those gaps get smaller — sometimes the track even buckles. Why? Because the metal expands when heated.
Or consider a mercury thermometer. The liquid mercury sits in a bulb at the bottom. When your body warms the bulb, the mercury expands and rises up the narrow tube. The hotter you are, the higher it climbs.
This is thermal expansion: most materials get bigger when heated and smaller when cooled. The atoms inside vibrate more vigorously as temperature rises, pushing their neighbours slightly farther apart. The entire object grows in every direction.
But different materials expand by different amounts. A steel rod and an aluminium rod of the same length, heated by the same amount, will not end up the same length. Aluminium expands more. So we need a number that tells us how much a given material expands per degree of temperature change. That number is the thermal expansion coefficient.
The Precise Statement: Defining the Coefficient
There are actually three coefficients, depending on whether we care about length, area, or volume. For a first meeting, we focus on the most common one: the linear thermal expansion coefficient, denoted by the Greek letter α (alpha).
α=L01⋅ΔTΔL
Where:
- L0 is the original length of the object (at some starting temperature)
- ΔL is the change in length (final length minus original length)
- ΔT is the change in temperature (final temperature minus initial temperature)
What this formula says in plain English: The coefficient α is the fractional change in length per degree of temperature change. If α=2.5×10−5per∘C, it means that for every 1∘C rise in temperature, the material expands by 0.0025% of its original length.
How to Use It: The Working Formula
From the definition, we can rearrange to get the practical formula:
ΔL=αL0ΔT
So the final length L after a temperature change is:
L=L0+ΔL=L0(1+αΔT)
For small temperature changes (say, less than 100∘C), this linear approximation is excellent. For very large changes, the coefficient itself may change slightly with temperature, but at the introductory level we treat α as constant.
A Concrete Example
A steel bridge girder is 50.00m long at 20∘C. The linear expansion coefficient of steel is α=1.2×10−5/∘C. How much longer is it on a 40∘C day?
Step 1: Identify the quantities.
- L0=50.00m
- ΔT=40−20=20∘C
- α=1.2×10−5/∘C
Step 2: Apply the formula.
ΔL=αL0ΔT=(1.2×10−5)(50.00)(20)
Step 3: Calculate.
ΔL=1.2×10−5×1000=0.012m=1.2cm
So the girder expands by 1.2cm. That is why bridges have expansion joints — without them, the structure would buckle.
Two Important Cousins: Area and Volume Expansion
For a thin sheet (like a metal plate), we care about area expansion. The area expansion coefficient is approximately 2α. For a solid object, the volume expansion coefficient is approximately 3α. These come from the same idea: if every linear dimension grows by a factor (1+αΔT), then area grows by (1+αΔT)2≈1+2αΔT, and volume by (1+αΔT)3≈1+3αΔT.
These approximations (2α and 3α) are valid only when αΔT is small compared to 1. For most solids and modest temperature changes, this is true. For gases, the expansion is much larger and a different treatment is needed.
What the Coefficient Tells Us About Materials
| Material | α (per ∘C) | Behaviour |
|----------|--------------------------------|-----------| …
For an isotropic solid the coefficient of volume expansion is three times the linear one: alpha_v = 3 alpha_l, so alpha_l = alpha_v/3. …
alpha_v = 3 alpha_l, hence alpha_l = alpha_v/3. Answer (B).
For an isotropic material a length increases as L = L0(1 + alpha_l dT) in each of the three dimensions. The volume V = L^3 then expands as V = V0(1 + alpha_l dT)^3, and to first order (1 + alpha_l dT)^3 is approximately 1 + 3 alpha_l dT. …
- CBSE 2026Set ANNUAL1 markMCQQ.The relation between the coefficient of volume expansion (αv) and the coefficient of linear expansion (αl) is(a) αl = 3αv(b) αl = αv/3(c) αl = αv(d) αl = 3/αv
›Reveal solutionSolution
alpha_v = 3 alpha_l, hence alpha_l = alpha_v/3. Answer (B).
For an isotropic material a length increases as L = L0(1 + alpha_l dT) in each of the three dimensions. The volume V = L^3 then expands as V = V0(1 + alpha_l dT)^3, and to first order (1 + alpha_l dT)^3 is approximately 1 + 3 alpha_l dT. …
- CBSE 2025Set ANNUAL1 markMCQQ.On which of the following properties of a body does the coefficient of thermal expansion depends? (A) Shape (B) Size (C) Temperature (D) Potential energy curve
›Reveal solutionSolution
Thermal expansion is governed by the shape of the interatomic potential energy curve, not the body's shape or size.
The coefficient of thermal expansion of a solid is essentially a material (microscopic) property: it depends on how the interatomic potential energy varies with atomic separation. If this potential were a perfectly symmetric (harmonic) well, atoms would simply vibrate more with heating but the mean separation would not shift, giving zero thermal expansion. Real interatomic potentials are anharmonic (asymmetric — the potential rises more steeply at short distances than it falls at large distances), so as thermal vibration amplitude increases with temperature …
- CBSE 2024Set ANNUAL1 markMCQQ.The density of mercury is 13.6gcm−3 at 0∘C and its coefficient of cubical expansion is 1.82×10−4∘C−1 then density of mercury at 50∘C is(a) 13.48gcm−3(b) 14gcm−3(c) 13.48×10−2gcm−3(d) none of these.
›Reveal solutionSolution
As mercury expands on heating, its density falls by a factor (1−γΔT), giving 13.48gcm−3.
Since mass is conserved while volume increases on heating, density decreases as ρ(T)=1+γΔTρ0≈ρ0(1−γΔT) for small γΔT, where γ is the coefficient of cubical (volume) expansion. Here ρ0=13.6gcm−3, γ=1.82×10−4∘C−1, ΔT=50∘C−0∘C=50∘C.
…
- CBSE 2019Set hz1 markQ.Define: Coefficient of linear expansion.
›Reveal solutionSolution
Coefficient of linear expansion (alpha) is the fractional increase in length of a solid per unit rise in temperature: alpha = deltaL / (L deltaT).
When a solid rod is heated, its length generally increases. The coefficient of linear expansion is defined as the increase in length per unit original length, per unit rise in temperature.
If a rod of original length L undergoes a change in length deltaL when its temperature rises by deltaT, then:
alpha = deltaL / (L x deltaT)
…
- CBSE 2019Set hz1 markQ.Define: Coefficient of superficial expansion.
›Reveal solutionSolution
Coefficient of superficial expansion (beta) is the fractional increase in surface area of a solid per unit rise in temperature: beta = deltaA / (A deltaT), and beta ~ 2 alpha.
When a solid is heated, its surface area also increases, along with its length. The coefficient of superficial (or areal) expansion is defined as the increase in area per unit original area, per unit rise in temperature.
If a solid of original surface area A undergoes a change in area deltaA when its temperature rises by deltaT, then:
beta = deltaA / (A x deltaT)
…
- CBSE 2019Set hz1 markQ.Define: Coefficient of volume expansion.
›Reveal solutionSolution
Coefficient of volume (cubical) expansion (gamma) is the fractional increase in volume of a substance per unit rise in temperature: gamma = deltaV / (V deltaT), and gamma ~ 3 alpha for isotropic solids.
When a solid, liquid, or gas is heated, its volume generally increases. The coefficient of volume (or cubical) expansion is defined as the increase in volume per unit original volume, per unit rise in temperature.
If a substance of original volume V undergoes a change in volume deltaV when its temperature rises by deltaT, then:
gamma = deltaV / (V x deltaT)
…
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