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Q.The path difference between the two waves y1 = a1 sin(ωt − 2πx/λ) and y2 = a2 cos(ωt − 2πx/λ + φ) is

(a) (2π/λ)φ
(b) (λ/2π)φ
(c) (2π/λ)(φ + π/2)
(d) (λ/2π)(φ + π/2)
Bihar BsebBihar Board Intermediate 1st Year 2026MCQ· 1mImportance★★★★★
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Convert cos to sin; extra phase = phi + pi/2; path difference = (lambda/2 pi)(phi + pi/2). Answer (D).

Given:

y1 = a1 sin(omega t - 2 pi x/lambda)

y2 = a2 cos(omega t - 2 pi x/lambda + phi).

Using cos(theta) = sin(theta + pi/2), rewrite y2:

y2 = a2 sin(omega t - 2 pi x/lambda + phi + pi/2).

Comparing the arguments of the two sine waves, the phase difference is:

delta_phi = (phi + pi/2).

…

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