Q.Which of the following statement(s) would give an error after executing the following code? stud={"Murugan":100, "Mithu":95} # Statement 1 print(stud[95]) # Statement 2 Stud["Murugan"]=99 # Statement 3 print(Stud.pop()) # Statement 4 print(Stud) # Statement 5

Concept: Dictionary access in Python — a dictionary is looked up by its keys, and a dictionary's pop() method must be given the key to remove.

The dictionary stud = {"Murugan": 100, "Mithu": 95} has the two names as keys and 100, 95 as values.

Statement 2 — print(stud[95]): 95 is a value, not a key. A dictionary can only be indexed by a key, so stud[95] raises a KeyError. This statement errors.

Statement 4 — print(Stud.pop()): unlike a list, a dictionary's pop() requires the key to remove as an argument. Calling pop() with no argument raises a TypeError. This statement errors. …

Understanding the code

stud = {"Murugan": 100, "Mithu": 95}   # Statement 1
print(stud[95])                         # Statement 2
Stud["Murugan"] = 99                    # Statement 3
print(Stud.pop())                       # Statement 4
print(Stud)                             # Statement 5

A dictionary stores key : value pairs. Here the keys are the strings "Murugan" and "Mithu", and the values are 100 and 95.

Why Statement 2 errors

stud[95] tries to use 95 as a key. But 95 is a value in the dictionary, not a key — you cannot look a dictionary up by its value using square brackets. Python therefore raises:

KeyError: 95

Why Statement 4 errors

For a list, pop() can be called with no argument (it removes the last item). For a dictionary, pop() must be told which key to remove, so it needs an argument. Calling it with none raises:

TypeError: pop expected at least 1 argument, got 0

So Statement 4 also errors. …