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NCERT Exemplar · Q64

Q.Match the following enzymes given in Column I with the reactions they catalyse given in Column II. Column I (Enzymes): (A) Invertase; (B) Maltase; (C) Pepsin; (D) Urease; (E) Zymase. Column II (Reactions):

(1) Decomposition of urea into NH3_3 and CO2_2;
(2) Conversion of glucose into ethyl alcohol;
(3) Hydrolysis of maltose into glucose;
(4) Hydrolysis of cane sugar;
(5) Hydrolysis of proteins into peptides.
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This is a matching problem linking enzymes to their specific biochemical reactions. The correct matches are: Invertase → hydrolysis of cane sugar (4), Maltase → hydrolysis of maltose into glucose (3), Pepsin → hydrolysis of proteins into peptides (5), Urease → decomposition of urea into NH₃ and CO₂ (1), Zymase → conversion of glucose into ethyl alcohol (2).

The key to solving this lies in understanding what each enzyme actually does — not just memorising names, but knowing the substrate it acts on and the product it yields. Enzymes are highly specific; each one catalyses a particular chemical transformation.

Let’s go through them one by one.

  1. Invertase (A) – This enzyme acts on sucrose (cane sugar). Sucrose is a disaccharide made of glucose and fructose. Invertase hydrolyses the glycosidic bond in sucrose, yielding an equimolar mixture of glucose and fructose, often called "invert sugar." So it matches with (4) Hydrolysis of cane sugar.

  2. Maltase (B) – Maltose is another disaccharide, composed of two glucose units linked by an α-1,4 bond. Maltase specifically hydrolyses this bond to produce two molecules of glucose. Hence it matches with (3) Hydrolysis of maltose into glucose.

  3. Pepsin (C) – This is a proteolytic enzyme (a protease) secreted in the stomach. It breaks down proteins into smaller peptide fragments (not individual amino acids — that comes later). So it matches with (5) Hydrolysis of proteins into peptides.

  4. Urease (D) – This enzyme catalyses the breakdown of urea into ammonia and carbon dioxide. Urea is a waste product from protein metabolism, and urease is found in certain bacteria and plants. The reaction is:

    CO(NH2)2+H2O→urease2NH3+CO2\text{CO(NH}_2)_2 + \text{H}_2\text{O} \xrightarrow{\text{urease}} 2\text{NH}_3 + \text{CO}_2

    So it matches with (1) Decomposition of urea into NH₃ and CO₂. …

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