Q.Fluorine exhibits only –1 oxidation state whereas other halogens exhibit +1, +3, +5 and +7 oxidation states also. Explain.
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →Step 1 — Fluorine's unique atomic properties.
Fluorine has the smallest atomic radius and the highest electronegativity of all elements. Its valence shell is : only and orbitals exist — there is no subshell.
Step 2 — Why F is restricted to –1.
Being the most electronegative element, fluorine has no atom that can pull electron density away from it, so it can never show a positive oxidation state — it always either gains an electron completely () or shares in a single covalent bond, effectively giving . With no valence orbitals to promote electrons into, it also cannot expand its octet to form multiple bonds.
Step 3 — Why other halogens show positive states. …
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.