Q.The degree of the differential equation is:
(A) 4
(B)
(C) not defined
(D) 2
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Start your 14-day free trial to unlock the full solution →The degree of a differential equation is defined only when the equation is a polynomial in the derivatives. Here, raising both sides to the power 2 gives a polynomial, so the degree is 2.
The degree of a differential equation is the power of the highest-order derivative, provided the equation is a polynomial in all the derivatives that appear. If the equation involves fractional powers, roots, or non-polynomial functions of the derivatives, the degree is not defined until we rewrite it as a polynomial — if possible.
In this problem, the highest-order derivative is , and it appears inside a square root (via the exponent on the left side). That fractional exponent is the obstacle: the equation is not yet a polynomial in the derivatives. So we must first remove the fractional power by raising both sides to a suitable integer power, then check the polynomial form.
Let’s work through it step by step.
- Identify the highest-order derivative. The equation is
The highest derivative present is (order 2). The degree concerns this derivative, but only after the equation is made polynomial in all derivatives.
- Remove the fractional exponent. The left side has exponent . To clear the square root, square both sides:
This gives
- Check if the equation is now a polynomial in derivatives. …
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