Skip to content
Question of 373

Q.Integrate ∫x2−1x2+4 dx\int \frac{x^2 - 1}{x^2 + 4}\,dx.

Bihar BsebBihar Board Intermediate 2024Subjective· 2mImportance★★★★★
0% · 0/373 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Splitting the improper fraction gives x−52tan⁡−1x2+Cx - \dfrac{5}{2}\tan^{-1}\dfrac{x}{2} + C.

Evaluate ∫x2−1x2+4 dx\displaystyle\int \dfrac{x^2-1}{x^2+4}\,dx.

Step 1 — write x2−1x2+4=(x2+4)−5x2+4=1−5x2+4\dfrac{x^2-1}{x^2+4} = \dfrac{(x^2+4)-5}{x^2+4} = 1 - \dfrac{5}{x^2+4}.

Step 2 — integrate term by term: ∫1 dx−5∫dxx2+22\displaystyle\int 1\,dx - 5\int\dfrac{dx}{x^2+2^2}.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.