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Q.∫x4+1x2+1 dx=\int \frac{x^4 + 1}{x^2 + 1}\,dx =

(a) x33+c\frac{x^3}{3} + c
(b) x33−x+2tan⁡−1x+c\frac{x^3}{3} - x + 2\tan^{-1} x + c
(c) 2tan⁡−1x+c2\tan^{-1} x + c
(d) x33+x+2tan⁡−1x+c\frac{x^3}{3} + x + 2\tan^{-1} x + c
Bihar BsebBihar Board Intermediate 2024MCQ· 1mImportance★★★★★
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Split the improper fraction by polynomial division: x4+1x2+1=x2−1+2x2+1\frac{x^4+1}{x^2+1} = x^2 - 1 + \frac{2}{x^2+1}.

Write x4+1=(x4−1)+2=(x2−1)(x2+1)+2x^4 + 1 = (x^4 - 1) + 2 = (x^2-1)(x^2+1) + 2. Dividing by x2+1x^2+1:

x4+1x2+1=x2−1+2x2+1.\frac{x^4+1}{x^2+1} = x^2 - 1 + \frac{2}{x^2+1}.

Integrate term by term: …

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