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Exercise 3.2 · Q22

Q.Assume XX, YY, ZZ, WW and PP are matrices of order 2×n2 \times n, 3×k3 \times k, 2×p2 \times p, n×3n \times 3 and p×kp \times k, respectively. If n=pn = p, then the order of the matrix 7X−5Z7X - 5Z is: (A) p×2p \times 2 (B) 2×n2 \times n (C) n×3n \times 3 (D) p×np \times n

Bihar BsebTextbookSubjective· 1mImportance★★★★★
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Matrix subtraction is only defined when both matrices have the same order. Since XX is 2×n2 \times n and ZZ is 2×p2 \times p, and we are given n=pn = p, both are 2×n2 \times n. So 7X−5Z7X - 5Z is also 2×n2 \times n, which matches option (B).

The key idea here is matrix compatibility for addition and subtraction. You can only add or subtract two matrices if they have exactly the same number of rows and the same number of columns. Multiplying a matrix by a scalar (like 7 or 5) does not change its order — it just scales every entry.

Let’s lay out what we know:

  1. Order of XX: 2×n2 \times n

    So XX has 2 rows and nn columns.

  2. Order of ZZ: 2×p2 \times p

    So ZZ has 2 rows and pp columns.

  3. Given condition: n=pn = p

    This means the number of columns in XX equals the number of columns in ZZ.

  4. Effect of scalar multiplication:

    7X7X still has order 2×n2 \times n, and 5Z5Z still has order 2×p2 \times p. Since n=pn = p, both 7X7X and 5Z5Z are 2×n2 \times n.

  5. Subtraction is defined:

    Because both matrices now have the same order (2×n2 \times n), 7X−5Z7X - 5Z is defined and its order remains 2×n2 \times n. …

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