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Q.Derive an expression for torque experienced by electric dipole placed in external electric field.

Bihar BsebBihar Board Intermediate 2026Subjective· 5mImportance★★★★★
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A dipole in a uniform field feels equal and opposite forces forming a couple; the torque is τ=pEsin⁡θ\tau = pE\sin\theta, or in vector form τ⃗=p⃗×E⃗\vec{\tau} = \vec{p}\times\vec{E}.

Setup. Consider an electric dipole consisting of charges +q+q and −q-q separated by a distance 2a2a, placed in a uniform external electric field E⃗\vec{E}. Let the dipole axis make an angle θ\theta with the direction of the field. The dipole moment is p⃗\vec{p}, of magnitude p=q(2a)p = q(2a), directed from −q-q to +q+q.

Step 1 — forces on the charges. The field exerts a force +qE+qE on the charge +q+q (along E⃗\vec{E}) and a force −qE-qE on the charge −q-q (opposite to E⃗\vec{E}). These two forces are equal in magnitude (qEqE) and opposite in direction, so the net force on the dipole is zero (in a uniform field).

Step 2 — they form a couple. Although the net force is zero, the two forces act along different lines of action, so they constitute a couple that tends to rotate the dipole and align it with the field. The torque of a couple = (magnitude of either force) × (perpendicular distance between the two forces).

Step 3 — perpendicular distance. From the geometry, the perpendicular distance between the lines of action of the two forces is

2asin⁡θ.2a\sin\theta.

Step 4 — magnitude of torque. …

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