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Q.Derive an expression for the torque acting on an electric dipole when placed in a uniform electric field.

Meghalaya MboseMBOSE Meghalaya Intermediate Board 2026Subjective· 2mImportance★★★★★
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The two equal, opposite forces on a dipole's charges in a uniform field produce zero net force but a net turning effect (couple), whose moment works out to τ=pEsin⁡θ=∣p⃗×E⃗∣\tau=pE\sin\theta=|\vec p\times\vec E|.

Setup

Consider an electric dipole consisting of charge −q-q at point AA and charge +q+q at point BB, separated by a distance 2a2a, placed in a uniform external electric field E⃗\vec E. The dipole moment p⃗\vec p has magnitude p=q(2a)p=q(2a) and points from −q-q to +q+q. Let θ\theta be the angle between p⃗\vec p and E⃗\vec E.

Forces on the two charges

Force on +q+q:  F⃗+=qE⃗\ \vec F_{+} = q\vec E (along E⃗\vec E)

Force on −q-q:  F⃗−=−qE⃗\ \vec F_{-} = -q\vec E (opposite to E⃗\vec E)

Net force

F⃗net=F⃗++F⃗−=qE⃗−qE⃗=0\vec F_{\text{net}}=\vec F_{+}+\vec F_{-}=q\vec E - q\vec E = 0

So the dipole experiences no net translational force in a uniform field — but since F⃗+\vec F_+ and F⃗−\vec F_- act at different points (separated perpendicular to the field direction), they constitute a couple, which produces a net torque.

Finding the torque (moment of the couple)

The perpendicular distance between the two parallel, oppositely-directed forces (the "arm" of the couple) is the projection of the separation 2a2a perpendicular to E⃗\vec E:

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