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Exercises · 1.5

Q.When a glass rod is rubbed with a silk cloth, charges appear on both. A similar phenomenon is observed with many other pairs of bodies. Explain how this observation is consistent with the law of conservation of charge.

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Rubbing transfers electrons from one body to the other, creating equal and opposite charges. The total charge before and after remains zero — this is the law of conservation of charge in action.

When you rub a glass rod with silk, the rod becomes positively charged and the silk negatively charged. This isn’t magic — it’s a transfer of electrons. The glass rod loses electrons to the silk, so the rod ends up with a net positive charge (more protons than electrons), and the silk gains those electrons, giving it a net negative charge.

The key point is that charge is never created or destroyed — it’s only moved from one place to another. Before rubbing, both the rod and the silk were electrically neutral. After rubbing, the total charge of the system (rod + silk) is still zero: the positive charge on the rod is exactly equal in magnitude to the negative charge on the silk.

This is exactly what the law of conservation of charge states: the net electric charge of an isolated system remains constant. Here, the system is the rod and silk together — no charge enters or leaves the pair.

Let’s walk through it step by step.

  1. Initial state: Both the glass rod and the silk cloth are neutral. That means each has an equal number of protons and electrons. The total charge of the system is

Qinitial=0+0=0.Q_{\text{initial}} = 0 + 0 = 0.

  1. During rubbing: The friction causes electrons to be transferred from the glass rod to the silk cloth. Glass holds its electrons less tightly than silk does, so electrons move from glass to silk.

    • The glass rod loses, say, nn electrons. Each electron has charge −e-e, so the rod’s charge becomes +ne+ne (since it now has nn more protons than electrons).
    • The silk gains those nn electrons, so its charge becomes −ne-ne.
  2. Final state: The rod has charge +ne+ne, the silk has charge −ne-ne. The total charge of the system is

    Qfinal=(+ne)+(−ne)=0.Q_{\text{final}} = (+ne) + (-ne) = 0. …

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